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A tower stands vertically on the ground. From a point on the g

Question

A tower stands vertically on the ground. From a point on the ground which is $30 m$ away from the foot of a tower, the angle of elevation of the top of the tower is found to be $4 5^{o}$ . Find the height of tower.

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Camila Discussed

A tower stands vertically on the ground. From a point on the ground which is

30 m

away from the foot of a tower, the angle of elevation of the top of the tower is found to be

4 5^{o}

. Find the height of tower.

6 mins ago

Discuss this question LIVE

6 mins ago

Text solutionVerified

REF.Image.

30 m

away /

4 5^{\circ}

inclination.

Let the height of tower be h m

A B = h m

Distance of the point from

foot of tower =

30 m

CB = 30 m

Angle of elevation

= 4 5^{\circ}

∠ A CB = 4 5^{\circ}

Since tower is vertical to ground

∠ A BC = 9 0^{\circ}

Now

t an C = \frac{s i d e o pp t o an g l e C}{s i d e a d ja ce n t t o an g l e C}

tan C = \frac{A B}{CB}

tan 45 = \frac{A B}{CB}

1 = \frac{H}{30}

H = 30

Hence height of tower =

30 m

Answer = option

C = 30 m

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Question Text	A tower stands vertically on the ground. From a point on the ground which is $30 m$ away from the foot of a tower, the angle of elevation of the top of the tower is found to be $4 5^{o}$ . Find the height of tower.
Answer Type	Text solution:1
Upvotes	151