A normal at any point (x,y) to the curve y=f(x) cuts a triangle of unit area with the axis, the differential equation of the curve is
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The solution of the differential equation x2dxdycos(x1)−ysin(x1)=−1, where y→−1 asx→∞ is
The gradient of the curve passing through (4, 0) is given by if the point (5, a) lies on the curve, then the value of a is
The order of the differential equation whose general solution is given by y=(C1+C2)cos(x+C3)−C4ex+C5, where C1,C2,C3,C4,C5 , are arbitrary constants, is (a) 5 (b) 4 (c) 3 (d) 2
The degree of differential equation satisfying the relation1+x2−−−−−√+1+y2−−−−−√=λ(x1+y2−−−−−√−y1+x2−−−−−√) is
The differential equation of the curve xc−1+yc+1=1 is given by
The solution to of the differential equation(x+1)dydx−y=e3x(x+1)2 is
The solution of is