A ladder has rungs 25 cm apart, (see Figure). The rungs decrease uniformly in length from 45 cm at the bottom to 25 cm at the top. If the top and the bottom rungs are $2 \frac{1}{2}$ m apart, what is the length of the wood required for the rungs?

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A ladder has rungs 25 cm apart, (see Figure). The rungs decrease uniformly in length from 45 cm at the bottom to 25 cm at the top. If the top and the bottom rungs are

2 \frac{1}{2}

m apart, what is the length of the wood required for the rungs?

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Text solutionVerified

Solution: Length of rugs is in AP
n=250/25=10
therefor, number of rugs=10

S = r_{1} + r_{2} + \dots + r_{10}

S_{10} = \frac{10}{2} (a + l)

S_{10} = 5 (45 + 25)

S_{10} = 350 c m

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Question Text	A ladder has rungs 25 cm apart, (see Figure). The rungs decrease uniformly in length from 45 cm at the bottom to 25 cm at the top. If the top and the bottom rungs are $2 \frac{1}{2}$ m apart, what is the length of the wood required for the rungs?
Answer Type	Text solution:1
Upvotes	150

A ladder has rungs 25 cm apart, (see Figure). The rungs decrease uniformly in length from 45 cm at the bottom to 25 cm at the top. If the top and the bottom rungs are 221​m apart, what is the length of the wood required for the rungs?

Text solutionVerified

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A ladder has rungs 25 cm apart, (see Figure). The rungs decrease uniformly in length from 45 cm at the bottom to 25 cm at the top. If the top and the bottom rungs are $2 \frac{1}{2}$ m apart, what is the length of the wood required for the rungs?