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A differential equation associated with the primitive y=a+be5x+ce− 7x is
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[b] y=a+be5x+ce−7x ? (i) ∴ y1=0+5be5x−7ce−7x Dividing by ye5x, we get: e−5xy1=5b−7ce−12x Again differentiating both sides w.r.t.x, we get e−5x.y2+y1(−5)e−5x=0+84ce−12x Dividing bye−12x. We get: e7x(y2−5y1)=84c Differentiating both sides w.r.t.x, we get e7x(y3−5y2)+(y2−5y1).7e7x=0 ⇒y3+2y2−35y1=0
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Let be the solution of the differential equation and then vaue of is equal to (a) (b) (c) (d) Stuck on the question or explanation?
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Question Text | A differential equation associated with the primitive y=a+be5x+ce− 7x is |
Answer Type | Text solution:1 |
Upvotes | 150 |