A box contains 5 red marbles, 8 white marbles and 4 green marbles. One marble is taken out of the box at random. What is the probability that the marble taken out will be(i) red ? (ii) white ? (iii) not green?

Question

A box contains 5 red marbles, 8 white marbles and 4 green marbles. One marble is taken out of the box at random. What is the probability that the marble taken out will be(i) red ?            (ii) white ?        (iii) not green?

Filo · Accepted Answer

Solution: Here, total number of marbles

n (S) = 5 + 8 + 4 = 17

Number of red marbles,

n (E_{r}) = 5

Number of white marbles,

n (E_{w}) = 8

Number of green marbles,

n (E_{g}) = 4

So, probablity marble taken is red,

P (E_{r}) = \frac{n ( E _{r} )}{n ( S )} = \frac{5}{17}

Probablity marble taken is white,

P (E_{w}) = \frac{n ( E _{r} )}{n ( S )} = \frac{8}{17}

Probablity marble taken is green,

P (E_{g}) = \frac{n ( E _{g} )}{n ( S )} = \frac{4}{17}

Probablity marble taken is not green,

= 1 - P (E_{g}) = 1 - \frac{4}{17} = \frac{13}{17}

Question Text	A box contains 5 red marbles, 8 white marbles and 4 green marbles. One marble is taken out of the box at random. What is the probability that the marble taken out will be(i) red ? (ii) white ? (iii) not green?
Answer Type	Text solution:1
Upvotes	150

A box contains 5 red marbles, 8 white marbles and 4 green marbles. One marble is taken out of the box at random. What is the probability that the marble taken out will be(i) red ? (ii) white ? (iii) not green?

Text solutionVerified

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