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{(-{A})}^{{-{1}}} is always equal to (where {A} is nth-order s

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$(- A)^{- 1}$ is always equal to (where $A$ is nth-order square matrix) $(- A)^{- 1}$ b. $- A^{- 1}$ c. $(- 1)^{n} A^{- 1}$ d. none of these

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Chloe Discussed

(- A)^{- 1}

is always equal to (where

A

is nth-order square matrix)

(- A)^{- 1}

- A^{- 1}

(- 1)^{n} A^{- 1}

d. none of these

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Question Text

(- A)^{- 1}

is always equal to (where

A

is nth-order square matrix)

(- A)^{- 1}

- A^{- 1}

(- 1)^{n} A^{- 1}

d. none of these

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