Which of the following has $p\pi -d\pi$ bonding?

In $S{O}_3^{2-}$ , S is $s{p}^3$ hybridised, so

$\underset{\left(\text{Sulphur atom in excited state}\right)}{{.}_{16}S=1s^2,2s^{2}2p^6},\underset{s{p}^3\text{hybridisation}}{\underbrace{3s^{2}3p_x^{1}3p_y^{1}3p_z^1}}\underset{\text{Unhybridised}}{3d_{xy}^1}$
In 'S' the three p-orbitals forms $\sigma$ bonds with three oxygen atoms and unhybridised d-orbital is involved in $\pi$-bond formation
$O_8=1s^2,2s^{2}2p_x^{2}2p_y^{1}2p_z^1$
In oxygen two unpaired p-orbitals are present , one is involved in $\sigma$ bond formation while other is used in $\pi$-bond formation.
Thus, in $S{O}_3^{2-}$ , p and d-orbitals are involved for $p\pi -d\pi$ bonding.