Which is correct curve for Charle's law, when the curve is plotted at 0.821 atm pressure for 10 mole ideal gas?

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Answer: bSolution: (b) V=KT
(i)

\frac{V}{T} = K

(ii)

V T = K T^{2}

(iii) log V = log K + log T

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Question Text	Which is correct curve for Charle's law, when the curve is plotted at 0.821 atm pressure for 10 mole ideal gas?
Answer Type	Text solution:1
Upvotes	151