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Group 13 elements - Electronic configuration, physical and chemical properties

When metal ' M ' is treated with {NaOH}, a white gelatinous pr

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When metal ' $M$ ' is treated with $NaOH$ , a white gelatinous precipitate ' $X$ ' is obtained, which is soluble in excess of $NaOH$ . Compound ' $X$ ' when heated strongly gives an oxide which is used in chromatography as an adsorbent. The metal ' $M$ ' is

Name: Video solution 1: When metal ' M ' is treated with NaOH, a white gelatinous precipitate ' X ' is obtained, which is soluble in excess of NaOH. Compound ' X ' when heated strongly gives an oxide which is used in chromatography as an adsorbent. The metal ' M ' is
Uploaded: 2022-06-05T16:13:10.000Z
Duration: 3 min
Description: Video solution 1: When metal ' M ' is treated with NaOH, a white gelatinous precipitate ' X ' is obtained, which is soluble in excess of NaOH. Compound ' X ' when heated strongly gives an oxide which is used in chromatography as an adsorbent. The metal ' M ' is

Zn

Ca

Al

Fe

Views: 5,887 students

Updated on: Jun 5, 2022

Book:

Arihant Chemistry JEE Main Chapterwise Solutions (2019-2002) (Arihant)

Exam:

JEE Mains 2018

Found 3 tutors discussing this question

Samuel Discussed

When metal '

M

' is treated with

NaOH

, a white gelatinous precipitate '

X

' is obtained, which is soluble in excess of

NaOH

. Compound '

X

' when heated strongly gives an oxide which is used in chromatography as an adsorbent. The metal '

M

' is

10 mins ago

Discuss this question LIVE

10 mins ago

Text solutionVerified

Among the given metals Al forms white gelatinous ppt. with

NaOH

. Hence, the probable metal can be Al. This ppt. is dissolved in excess of

NaOH

due to the formation of sodium metal Aluminate. Both the reactions are shown below. Solution Image

Aluminium hydroxide on strong heating gives alumina

(Al_{2} O_{3})

which is used as an adsorbent in chromatography. This reaction can be seen as :

2 Al (OH)_{3} ⟶ Δ Al_{2} O_{3} + 3 H_{2} O

Thus, metal

M

Al

. Ca, being below sodium in electrochemical reactivity series, cannot displaces

Na

from its aqueous solution.

Zn

reacts with

NaOH

to form sodium zincate which is a soluble compound.

Fe

reacts with sodium hydroxide to form tetrahydroferrate (II) sodium which is again a soluble complex.

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Question Text	When metal ' $M$ ' is treated with $NaOH$ , a white gelatinous precipitate ' $X$ ' is obtained, which is soluble in excess of $NaOH$ . Compound ' $X$ ' when heated strongly gives an oxide which is used in chromatography as an adsorbent. The metal ' $M$ ' is
Updated On	Jun 5, 2022
Topic	The p-Block Elements
Subject	Chemistry
Class	Class 11
Answer Type	Text solution:1 Video solution: 1
Upvotes	171
Avg. Video Duration	3 min

When metal ' $M$ ' is treated with $NaOH$ , a white gelatinous precipitate ' $X$ ' is obtained, which is soluble in excess of $NaOH$ . Compound ' $X$ ' when heated strongly gives an oxide which is used in chromatography as an adsorbent. The metal ' $M$ ' is

Text solutionVerified

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When metal ' M ' is treated with NaOH, a white gelatinous precipitate ' X ' is obtained, which is soluble in excess of NaOH. Compound ' X ' when heated strongly gives an oxide which is used in chromatography as an adsorbent. The metal ' M ' is

Text solutionVerified

Filo tutor solutions (1)

Questions from JEE Mains 2018 - PYQs

Practice questions from Arihant Chemistry JEE Main Chapterwise Solutions (2019-2002) (Arihant)

Practice questions from The p-Block Elements in the same exam

Practice more questions from The p-Block Elements

Practice questions on similar concepts asked by Filo students

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Previous year question papers

When metal ' $M$ ' is treated with $NaOH$ , a white gelatinous precipitate ' $X$ ' is obtained, which is soluble in excess of $NaOH$ . Compound ' $X$ ' when heated strongly gives an oxide which is used in chromatography as an adsorbent. The metal ' $M$ ' is