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What is the density of wet air with 75% relative humidity at 1

Question

What is the density of wet air with 75% relative humidity at 1 atm and 300 K? Given : vapour pressure of $H_{2} O$ is 30 torr and average molar mass of air is 29 g $m o l^{_{1}}$ .

1.614 g/L

0.96 g/L

1.06 g/L

1.164 g/L

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What is the density of wet air with 75% relative humidity at 1 atm and 300 K? Given : vapour pressure of

H_{2} O

is 30 torr and average molar mass of air is 29 g

m o l^{_{1}}

8 mins ago

Discuss this question LIVE

8 mins ago

Text solutionVerified

Answer: dSolution: (d) % Relative humidity

= \frac{Partial pressure of H _{2} O}{Vapour pressure of H _{2} O} \times 100

75 = \frac{P _{H_{2} O}}{30} \times 100

P_{H_{2} O} = 22.5 torr,

% of

H_{2} O

vapour in air

= \frac{( 22.5 )}{760} \times 100 = 2.96

molar mass of wet air

= \frac{29 \times 97.04 + 2.96 \times 18}{100}

= \frac{2814.16 + 53.28}{100} = 28.67

density of wet air

= \frac{P M}{R T} = \frac{1 \times 28.67}{0.0821 \times 300}

= 1.164 g / L

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Question Text	What is the density of wet air with 75% relative humidity at 1 atm and 300 K? Given : vapour pressure of $H_{2} O$ is 30 torr and average molar mass of air is 29 g $m o l^{_{1}}$ .
Answer Type	Text solution:1
Upvotes	150