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What is the compressibility factor (Z) for 0.02 mole of a van

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What is the compressibility factor (Z) for 0.02 mole of a van der Waals's gas at pressure of 0.1 atm. Assume the size of gas molecules is negligible.
Given : RT=20 L atm $m o l^{- 1}$ and a=1000 atm $L^{2} m o l^{- 2}$

0.02

0.5

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What is the compressibility factor (Z) for 0.02 mole of a van der Waals's gas at pressure of 0.1 atm. Assume the size of gas molecules is negligible.
Given : RT=20 L atm

m o l^{- 1}

and a=1000 atm

L^{2} m o l^{- 2}

12 mins ago

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12 mins ago

Text solutionVerified

Answer: dSolution: (d)

(0.1 + \frac{1000 \times ( 0.02 ) ^{2}}{V ^{2}}) V = 20 \times 0.02

= 0.1 V^{2} - 0.4 V + 0.4 = 0

= V^{2} - 4 V + 4 = 0

\Rightarrow V = 2 L

Z = \frac{P V}{n R T} = \frac{0.1 \times 2}{20 \times 0.02} = 0.5

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Question Text	What is the compressibility factor (Z) for 0.02 mole of a van der Waals's gas at pressure of 0.1 atm. Assume the size of gas molecules is negligible. Given : RT=20 L atm $m o l^{- 1}$ and a=1000 atm $L^{2} m o l^{- 2}$
Answer Type	Text solution:1
Upvotes	157

What is the compressibility factor (Z) for 0.02 mole of a van der Waals's gas at pressure of 0.1 atm. Assume the size of gas molecules is negligible. Given : RT=20 L atm mol−1 and a=1000 atm L2mol−2

Text solutionVerified

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What is the compressibility factor (Z) for 0.02 mole of a van der Waals's gas at pressure of 0.1 atm. Assume the size of gas molecules is negligible.
Given : RT=20 L atm $m o l^{- 1}$ and a=1000 atm $L^{2} m o l^{- 2}$