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Under identical conditions of pressure and temperature, 4 L of

Question

Under identical conditions of pressure and temperature, 4 L of gaseous moxture ( $H_{2}$ and $C H_{4}$ ) effuses through a hole in 5 min whereas 4 L of a gas X of molecular mass 36 takes to 10 min to effuse through the same hole. The mole ratio of $H_{2} : C H_{4}$ in the mixture is:

1 : 2

2 : 1

2 : 3

1 : 1

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Under identical conditions of pressure and temperature, 4 L of gaseous moxture (

H_{2}

and

C H_{4}

) effuses through a hole in 5 min whereas 4 L of a gas X of molecular mass 36 takes to 10 min to effuse through the same hole. The mole ratio of

H_{2} : C H_{4}

in the mixture is:

6 mins ago

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6 mins ago

Text solutionVerified

Answer: dSolution: (d)

\frac{r _{rmx}}{r _{x}} = \frac{4 / 5}{4 / 10} = 2 = \frac{M _{x}}{M _{mix}}

\Rightarrow M_{mix} = 9

M_{mix} = M_{H_{2}} X_{H_{2}} + M_{C H_{4}} X_{C H_{4}}

= 2 X_{H_{2}} + 16 (1 - X_{H_{2}}) = 9

\Rightarrow X_{H_{2}} = 0.5

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Question Text	Under identical conditions of pressure and temperature, 4 L of gaseous moxture ( $H_{2}$ and $C H_{4}$ ) effuses through a hole in 5 min whereas 4 L of a gas X of molecular mass 36 takes to 10 min to effuse through the same hole. The mole ratio of $H_{2} : C H_{4}$ in the mixture is:
Answer Type	Text solution:1
Upvotes	150