Two vessels connected by a valve of negligible volume. One container (I) has 2.8 g of N2 at temperature T1(K). The other container (II) is completely evacuated. The container (I) is heated to T2(K)while container (II) is maintained at T2/3(K). volume of vessel (I) is half that of vessel (II). If the valve is opened then what is the mass ratio of N2 is both vessel (WI/WII)?

Question

Two vessels connected by a valve of negligible volume. One container (I) has 2.8 g of N2​ at temperature T1​(K). The other container (II) is completely evacuated. The container (I) is heated to T2​(K)while container (II) is maintained at T2​/3(K). volume of vessel (I) is half that of vessel (II). If the valve is opened then what is the mass ratio of N2​ is both vessel (WI​/WII​)?

Filo · Accepted Answer

Answer: cSolution: (c)   Let x mole of N2​ present into vessel II and P is final pressure of N2​  P(2V)=xR(T2​/3)andP(V)=(0.1−x)RT2​  ⇒   2=3(0.1−x)x​  ⇒   x=0.6/7moles,  70.6​×28⇒2.4gN2​  II has 2.4 g N2​ and I has 0.4 g of N2​,  WII​WI​​=2.40.4​⇒1:6

Question Text	Two vessels connected by a valve of negligible volume. One container (I) has 2.8 g of $N_{2}$ at temperature $T_{1} (K)$ . The other container (II) is completely evacuated. The container (I) is heated to $T_{2} (K)$ while container (II) is maintained at $T_{2} / 3 (K)$ . volume of vessel (I) is half that of vessel (II). If the valve is opened then what is the mass ratio of $N_{2}$ is both vessel $(W_{I} / W_{I I})$ ?
Answer Type	Text solution:1
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