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Two gases A and B having the same volume diffuse through a por

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Medium

Solving time: 3 mins

Two gases $A$ and $B$ having the same volume diffuse through a porous partition in 20 and 10 seconds respectively. The molecular mass of $A$ is $49 u$ . Molecular mass of $B$ will be

50.00 u

12.25 u

6.50 u

25.00 u

Views: 5,406 students

Updated on: Oct 5, 2023

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Two gases

A

and

B

having the same volume diffuse through a porous partition in 20 and 10 seconds respectively. The molecular mass of

A

49 u

. Molecular mass of

B

will be

10 mins ago

Discuss this question LIVE

10 mins ago

Text solutionVerified

Using Graham's law of diffusion

\frac{r _{1}}{r _{2}} = \frac{m _{2}}{m _{1}}

\frac{V /20}{V /10} = \frac{m _{2}}{49}

\frac{1}{2} = \frac{m _{2}}{49}

m_{2} = 12 u

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Question Text	Two gases $A$ and $B$ having the same volume diffuse through a porous partition in 20 and 10 seconds respectively. The molecular mass of $A$ is $49 u$ . Molecular mass of $B$ will be
Updated On	Oct 5, 2023
Topic	States of Matter
Subject	Chemistry
Class	Class 11
Answer Type	Text solution:1 Video solution: 16
Upvotes	1676
Avg. Video Duration	6 min

Two gases $A$ and $B$ having the same volume diffuse through a porous partition in 20 and 10 seconds respectively. The molecular mass of $A$ is $49 u$ . Molecular mass of $B$ will be

Text solutionVerified

Filo tutor solutions (16)

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Two gases A and B having the same volume diffuse through a porous partition in 20 and 10 seconds respectively. The molecular mass of A is 49u. Molecular mass of B will be

Text solutionVerified

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Two gases $A$ and $B$ having the same volume diffuse through a porous partition in 20 and 10 seconds respectively. The molecular mass of $A$ is $49 u$ . Molecular mass of $B$ will be