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Two Faraday of electricity is passed through a solution of {Cu

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Two Faraday of electricity is passed through a solution of $CuSO_{4}$ . The mass of copper deposited at the cathode is (at. mass of $Cu = 63.5 u$ )

Name: Video solution 1: Two Faraday of electricity is passed through a solution of CuSO4. The mass of copper deposited at the cathode is (at. mass of Cu=63.5u )
Uploaded: 2023-02-26T12:27:32.000Z
Duration: 10 min
Description: Video solution 1: Two Faraday of electricity is passed through a solution of CuSO4. The mass of copper deposited at the cathode is (at. mass of Cu=63.5u )

0 g

63.5 g

2 g

127 g

Views: 5,836 students

Updated on: Feb 26, 2023

Book:

Arihant Chemistry JEE Main Chapterwise Solutions (2019-2002) (Arihant)

Exam:

JEE Mains 2015

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Olivia Discussed

Two Faraday of electricity is passed through a solution of

CuSO_{4}

. The mass of copper deposited at the cathode is (at. mass of

Cu = 63.5 u

)

10 mins ago

Discuss this question LIVE

10 mins ago

Text solutionVerified

Given,

Q = 2 F

Atomic mass of

Cu = 63.5 u

Valency of the metal

Z = 2

We have,

CuSO_{4} ⟶

Cu^{2 +} + SO_{4}^{2 -}

Cu^{2 +} + 2 e^{-} ⟶ Cu

1 mol 2 mol

2 F

1 mol = 63.5 g

Alternatively,

W = ZQ = \frac{E}{F} \cdot 2 F = 2 E = \frac{2 \times 63.5}{2}

=63.5

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Question Text	Two Faraday of electricity is passed through a solution of $CuSO_{4}$ . The mass of copper deposited at the cathode is (at. mass of $Cu = 63.5 u$ )
Updated On	Feb 26, 2023
Topic	Electrochemistry
Subject	Chemistry
Class	Class 12
Answer Type	Text solution:1 Video solution: 2
Upvotes	353
Avg. Video Duration	7 min

Two Faraday of electricity is passed through a solution of $CuSO_{4}$ . The mass of copper deposited at the cathode is (at. mass of $Cu = 63.5 u$ )

Text solutionVerified

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Two Faraday of electricity is passed through a solution of $CuSO_{4}$ . The mass of copper deposited at the cathode is (at. mass of $Cu = 63.5 u$ )