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Rate of chemical reaction

The rate laws for the reaction: {RCl}+{NaOH} (aq.) {ROH}+{NaC

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Hard

Solving time: 4 mins

The rate laws for the reaction:
$RCl + NaOH$ (aq.) $⟶ ROH + NaCl$ is given by, Rate $= k_{1} [RCl]$ . The rate of the reaction will be

Name: Video solution 1: The rate laws for the reaction: RCl+NaOH (aq.) ⟶ROH+NaCl is given by, Rate =k1[RCl]. The rate of the reaction will be
Uploaded: 2022-08-20T04:54:35.000Z
Duration: 8 min
Description: Video solution 1: The rate laws for the reaction: RCl+NaOH (aq.) ⟶ROH+NaCl is given by, Rate =k1[RCl]. The rate of the reaction will be

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doubled on doubling the concentration of sodium hydroxide.

halved on reducing the concentration of alkyl halide to one half.

increased on increasing the temperature of the reaction.

unaffected by increasing the temperature of the reaction.

Views: 6,026 students

Updated on: Aug 20, 2022

Book:

Physical Chemistry II for IIT JEE Main and Advance (McGraw Hill)

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Alexander Discussed

The rate laws for the reaction:

RCl + NaOH

(aq.)

⟶ ROH + NaCl

is given by, Rate

= k_{1} [RCl]

. The rate of the reaction will be

8 mins ago

Discuss this question LIVE

8 mins ago

Text solutionVerified

(b, c) R \propto K

K = A e^{- \frac{E a}{RT}}

∴

on increasing temperature rate constant increases

∴

Rate increased.

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Question Text	The rate laws for the reaction: $RCl + NaOH$ (aq.) $⟶ ROH + NaCl$ is given by, Rate $= k_{1} [RCl]$ . The rate of the reaction will be
Updated On	Aug 20, 2022
Topic	Chemical Kinetics
Subject	Chemistry
Class	Class 12
Answer Type	Text solution:1 Video solution: 1
Upvotes	218
Avg. Video Duration	8 min

The rate laws for the reaction:
$RCl + NaOH$ (aq.) $⟶ ROH + NaCl$ is given by, Rate $= k_{1} [RCl]$ . The rate of the reaction will be

Text solutionVerified

Filo tutor solutions (1)

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The rate laws for the reaction:
$RCl + NaOH$ (aq.) $⟶ ROH + NaCl$ is given by, Rate $= k_{1} [RCl]$ . The rate of the reaction will be