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The number of moles of {K}{M}{n}{O}_{{{4}}} that will be neede

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The number of moles of $K M n O_{4}$ that will be needed to react with $1 m o l$ of sulphite ion in acidic solution is

4 / 5

2 / 5

3 / 5

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The number of moles of

K M n O_{4}

that will be needed to react with

1 m o l

of sulphite ion in acidic solution is

6 mins ago

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6 mins ago

Text solutionVerified

2 K M n O_{4} + 3 H_{2} S O_{4} \to K_{2} S O_{4} + 2 M n S O_{4} + 3 H_{2} O + 5 [O]

[M n O_{4}^{-} + 8 H^{+} + 5 e^{-} \to M n^{2 +} + 4 H_{2} O] \times 2

[S O_{3}^{2 -} + H_{2} O \to S O_{4}^{2 -} + 2 H^{+} + 2 e^{-}] \times 5

2 M n O_{4}^{-} + 6 H^{+} + 5 S O_{3}^{2 -} \to 2 M n^{2 +} + 5 S O_{4}^{2 -} + 3 H_{2} O

5 moles of sulphite ions react with =2 moles of

M n O_{4}^{-}

So , 1 mole of sulphite ions react with

= \frac{2}{5} moles of M n O_{4}^{-}

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Question Text	The number of moles of $K M n O_{4}$ that will be needed to react with $1 m o l$ of sulphite ion in acidic solution is
Answer Type	Text solution:1
Upvotes	150