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The molecular weight of a gas which diffuse through a porous p

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Solving time: 3 mins

The molecular weight of a gas which diffuse through a porous plug of $1/6$ th of the speed of hydrogen under identical conditions is (in $u$ ):

27

72

36

48

Views: 6,624 students

Updated on: Jun 12, 2023

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The molecular weight of a gas which diffuse through a porous plug of

1/6

th of the speed of hydrogen under identical conditions is (in

u

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Text solutionVerified

Molecular weight of

H_{2} = M_{1} = 2 u

Rate of diffusion of

H_{2} = r_{1} = r

Unknown gas
Molecular weight of unknown gas

= M_{2} = x = ?

Rate of diffusion of unknown gas

= r_{2} = r /6

Since, According to Graham’s Law, at constant pressure and temperature, molecules or atoms with lower molecular mass will effuse faster than the higher molecular mass molecules or atoms. In other words, it states that rate of effusion of gas is inversely proportional to the square root of its molecular mass.

\frac{Rate _{1}}{Rate _{2}} = \frac{M _{2}}{M _{1}}

So,

\frac{r _{1}}{r _{2}} = \frac{M _{2}}{M _{1}} \Rightarrow \frac{r}{r /6} = \frac{M _{2}}{2} \Rightarrow 6 = \frac{x}{2} \Rightarrow 36 = \frac{x}{2} \Rightarrow x = 72 u

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Question Text	The molecular weight of a gas which diffuse through a porous plug of $1/6$ th of the speed of hydrogen under identical conditions is (in $u$ ):
Updated On	Jun 12, 2023
Topic	States of Matter
Subject	Chemistry
Class	Class 11
Answer Type	Text solution:1 Video solution: 6
Upvotes	702
Avg. Video Duration	4 min

The molecular weight of a gas which diffuse through a porous plug of $1/6$ th of the speed of hydrogen under identical conditions is (in $u$ ):

Text solutionVerified

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The molecular weight of a gas which diffuse through a porous plug of $1/6$ th of the speed of hydrogen under identical conditions is (in $u$ ):