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Question

The labelled $- O^{18}$ will be in :

H_{2} O

Methyl benzoate

Both (a) and (b)

Benzoic acid

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The labelled

- O^{18}

will be in :

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Text solutionVerified

Answer: BSolution: In esterification acid gives

O H^{ɵ}

whereas alcohol gives

H^{+}

.
Product of the reaction is methyl benzoate

P h - C ∣ ∣ O - O 18 - C H_{3}

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