The edge length of a face-centred cubic unit cell is 508±. If the radius of the cation is 110± the radius of the anion is

Edge length (a) = 2r++2r− a=2(r++r−) a = 508 pm r+=110pm 2508=r++r− 254=110+r− r−=254−110=144 pm

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The edge length of a face-centred cubic unit cell is {508}. If

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The edge length of a face-centred cubic unit cell is $508 \pm$ . If the radius of the cation is $110 \pm$ the radius of the anion is

288 pm

398 pm

144 pm

618 pm

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The edge length of a face-centred cubic unit cell is

508 \pm

. If the radius of the cation is

110 \pm

the radius of the anion is

14 mins ago

Discuss this question LIVE

14 mins ago

Edge length (a) =

2 r^{+} + 2 r^{-}

a = 2 (r^{+} + r^{-})

a = 508 pm

r^{+} = 110 pm

\frac{508}{2} = r^{+} + r^{-}

254 = 110 + r^{-}

r^{-} = 254 - 110 = 144 pm

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Question Text	The edge length of a face-centred cubic unit cell is $508 \pm$ . If the radius of the cation is $110 \pm$ the radius of the anion is
Answer Type	Text solution:1
Upvotes	150