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The coordination number of {N}{i}^{{{2}+}} is 4 {N}{i}{C}{I}_{

Question

The coordination number of $N i^{2 +}$ is 4
$N i C I_{2} + K C N$ (excess) gives $A$ (cyano complex)
$N i C I_{2} + c o n c . H C I$ (excess) gives $B$ (Chloro complex)
The $I U P A C$ name of $A$ and $B$ are .

potassium tetracyanonickelate (II), potassium tetrachloronickelate (II)

tetracyanopotassiumnickelate (II), tetrachloropotassiumnickelate (II)

tetracyanonickel (II), tetrachloronickel (II)

potassium tetracyanonickel (II), potassium tetrachloronickel (II)

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Ava Discussed

The coordination number of

N i^{2 +}

is 4

N i C I_{2} + K C N

(excess) gives

A

(cyano complex)

N i C I_{2} + c o n c . H C I

(excess) gives

B

(Chloro complex)
The

I U P A C

name of

A

and

B

are .

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Text solutionVerified

Answer: A

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Question Text	The coordination number of $N i^{2 +}$ is 4 $N i C I_{2} + K C N$ (excess) gives $A$ (cyano complex) $N i C I_{2} + c o n c . H C I$ (excess) gives $B$ (Chloro complex) The $I U P A C$ name of $A$ and $B$ are .
Answer Type	Text solution:1
Upvotes	150