The average speed at temperature T∘C of CH4(g) is 8828×103ms−1. What is the value of T ?

Answer: bSolution: (b) πM8RT=8828=227 π×16×10−38×8.314×T=227×106 T=8.3141000×2=240.55K T∘C=240.55−273=−32.45∘C

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The average speed at temperature {T}^{{}}{C} of {C}{H}_{{{4}}}

Question

The average speed at temperature $T^{\circ} C$ of $C H_{4} (g)$ is $\frac{28}{88} \times 10^{3} m s^{- 1}$ . What is the value of T ?

240.55^{\circ} C

- 32.45^{\circ} C

3000^{\circ} C

- 24.055^{\circ} C

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The average speed at temperature

T^{\circ} C

C H_{4} (g)

\frac{28}{88} \times 10^{3} m s^{- 1}

. What is the value of T ?

9 mins ago

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Answer: bSolution: (b)

\frac{8 R T}{π M} = \frac{28}{88} = \frac{7}{22}

\frac{8 \times 8.314 \times T}{π \times 16 \times 10 ^{- 3}} = \frac{7}{22} \times 10^{6}

T = \frac{1000 \times 2}{8.314} = 240.55 K

T^{\circ} C = 240.55 - 273 = - 32.45^{\circ} C

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Question Text	The average speed at temperature $T^{\circ} C$ of $C H_{4} (g)$ is $\frac{28}{88} \times 10^{3} m s^{- 1}$ . What is the value of T ?
Answer Type	Text solution:1
Upvotes	150