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we can condense vapour simply by applying pressure

to liquefy a gas one must lower the temperature below

T_{C}

and also apply pressure

T_{C}

there is no distinction between liquid and vapour state hence density of the liquid is nearly equal to density of the vapour

However great the pressure applied, a gas cannot be liquified below it's critical temp.

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Answer: dSolution: (d)

T_{Liquifaction \propto \frac{1}{I . M . A . F} \propto \frac{1}{a} \propto \frac{1}{T _{C}}}

\displaystyle{C}{r}{i}{t}{i}{c}{a}{l}{t}{e}{m}{p}{e}{r}{a}{t}{u}{r}{e}{i}{s}{a}{t}{e}{m}{p}{e}{r}{a}{t}{u}{r}{e}{a}{b}{o}{v}{e}{w}{h}{i}{c}{h}{a}{g}{a}{s}{c}{a}{n}'{t}{b}{e}{l}{i}{q}{u}{\quad\text{if}\quad}{y}.

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Answer Type	Text solution:1
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Select incorrect statement :

Text solutionVerified

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