Pressure of 1 g ideal gas X at 300 K is 2 atm. When 2 g of another gas Y is introduced in the same vessel at same temperature, the pressure become 3 atm. The correct relationship between molar mass of X and Y is :

M_{Y} = 2 M_{X}

M_{Y} = 4 M_{X}

M_{X} = 4 M_{Y}

None of these

Views: 2,176 students

Found 7 tutors discussing this question

Jack Discussed

Pressure of 1 g ideal gas X at 300 K is 2 atm. When 2 g of another gas Y is introduced in the same vessel at same temperature, the pressure become 3 atm. The correct relationship between molar mass of X and Y is :

10 mins ago

Discuss this question LIVE

10 mins ago

Text solutionVerified

Answer: bSolution: (b)

P \times N

\frac{P _{x}}{P _{y}} = \frac{n _{x}}{n _{y}}

\frac{2}{1} = \frac{1 / m _{x}}{2 / m _{y}}

m_{y} = 4 m_{x}

Was this solution helpful?

153

Report

One destination for complete JEE/NEET preparation

One destination to cover all your homework and assignment needs

Learn Practice Revision Succeed

Instant 1:1 help, 24x7

60, 000+ Expert tutors

Textbook solutions

Big idea maths, McGraw-Hill Education etc

Essay review

Get expert feedback on your essay

Schedule classes

High dosage tutoring from Dedicated 3 experts

Trusted by 4 million+ students

Stuck on the question or explanation?

Connect with our chemistry tutors online and get step by step solution of this question.

231 students are taking LIVE classes

Question Text	Pressure of 1 g ideal gas X at 300 K is 2 atm. When 2 g of another gas Y is introduced in the same vessel at same temperature, the pressure become 3 atm. The correct relationship between molar mass of X and Y is :
Answer Type	Text solution:1
Upvotes	153

Pressure of 1 g ideal gas X at 300 K is 2 atm. When 2 g of another gas Y is introduced in the same vessel at same temperature, the pressure become 3 atm. The correct relationship between molar mass of X and Y is :

Text solutionVerified

Practice questions from similar books