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Percentage of Se in peroxidase anhydrase enzyme is {0.5}% by w

Question

Percentage of Se in peroxidase anhydrase enzyme is $0.5 %$ by weight (at. Wt. $= 78.4)$ , then minimum molecular weight of peroxidase anhydrase enzyme is:

1.568 \times 10^{3}

15.68

2.168 \times 10^{4}

1.568 \times 10^{4}

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Alexander Discussed

Percentage of Se in peroxidase anhydrase enzyme is

0.5 %

by weight (at. Wt.

= 78.4)

, then minimum molecular weight of peroxidase anhydrase enzyme is:

15 mins ago

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15 mins ago

Text solutionVerified

Suppose the molecular weight of enzyme

= x 0.5 %

by weight means in 100 g of enzyme weight of Se =0.5 g

∴

in x g of enzyme weight of Se

= \frac{0.5}{100} \times X

Hence,

78.4 = \frac{0.5 \times x}{100}

X = 15680 = 1.568 \times 10^{4}

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Question Text	Percentage of Se in peroxidase anhydrase enzyme is $0.5 %$ by weight (at. Wt. $= 78.4)$ , then minimum molecular weight of peroxidase anhydrase enzyme is:
Answer Type	Text solution:1
Upvotes	151