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If you are given Avogadro's number of atoms of a gas X. If hal

Question

If you are given Avogadro's number of atoms of a gas $X$ . If half of the atoms are converted into $X_{(g)}^{+}$ by energy $Δ H$ . The IE of $X$ is :

\frac{2Δ H}{N _{A}}

\frac{2 N _{A}}{Δ H}

\frac{Δ H}{2 N _{A}}

\frac{N _{A}}{Δ H}

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If you are given Avogadro's number of atoms of a gas

X

. If half of the atoms are converted into

X_{(g)}^{+}

by energy

Δ H

. The IE of

X

is :

10 mins ago

Discuss this question LIVE

10 mins ago

Text solutionVerified

Given no. of atoms = Avogadro's no. of atoms =

N_{A} = 6.023 \times 10^{23}

Given that

\frac{N _{A}}{2}

atoms are ionized, i.e.,

Ionization energy of

\frac{N _{A}}{2}

atoms of gas X =

Δ H

∴

Ionization energy of 1 atom of gas X =

\frac{Δ H}{( \frac{N _{A}}{2} )} = \frac{2.Δ H}{N _{A}}

Hence, Ionisation energy of gas X is

\frac{2.Δ H}{N _{A}}

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Question Text	If you are given Avogadro's number of atoms of a gas $X$ . If half of the atoms are converted into $X_{(g)}^{+}$ by energy $Δ H$ . The IE of $X$ is :
Answer Type	Text solution:1
Upvotes	154