Get 2 FREE Instant-Explanations on Filo with code FILOAPP

If the slope of 'Z' (compressibility factor) vs. 'p' curve is

Question

If the slope of 'Z' (compressibility factor) vs. 'p' curve is constant $(slope = \frac{π}{492.6} a t m^{- 1})$ at a particular temperature (300 K) abd very high pressure, then calculate diameter of the molecules.
(Given : $N_{A} = 6.0 \times 10^{23}, R = 0.0821 a t m . L m o l^{- 1} K^{- 1}$ )

7.5 Å

5 Å

2.5 Å

1.25 Å

Views: 1,031 students

Found 7 tutors discussing this question

Henry Discussed

If the slope of 'Z' (compressibility factor) vs. 'p' curve is constant

(slope = \frac{π}{492.6} a t m^{- 1})

at a particular temperature (300 K) abd very high pressure, then calculate diameter of the molecules.
(Given :

N_{A} = 6.0 \times 10^{23}, R = 0.0821 a t m . L m o l^{- 1} K^{- 1}

)

6 mins ago

Discuss this question LIVE

6 mins ago

Text solutionVerified

Answer: bSolution: (b)

Z = 1 + \frac{P b}{R T}

at high pressure
slope

= \frac{b}{R T} = \frac{π}{492.6}

\Rightarrow b = \frac{π}{492.6} \times 0.0821 \times 300 and

b = \frac{4}{3} π r^{3} \times 4 N_{A}

= \frac{π}{492.6} \times 0.0821 \times 300 \times 10^{- 3}

\Rightarrow r = 2.5 \overset{˚}{A} or d = 5 \overset{˚}{A}

Was this solution helpful?

150

Report

One destination to cover all your homework and assignment needs

Learn Practice Revision Succeed

Instant 1:1 help, 24x7

60, 000+ Expert tutors

Textbook solutions

Big idea maths, McGraw-Hill Education etc

Essay review

Get expert feedback on your essay

Schedule classes

High dosage tutoring from Dedicated 3 experts

Trusted by 4 million+ students

Stuck on the question or explanation?

Connect with our chemistry tutors online and get step by step solution of this question.

231 students are taking LIVE classes

Question Text	If the slope of 'Z' (compressibility factor) vs. 'p' curve is constant $(slope = \frac{π}{492.6} a t m^{- 1})$ at a particular temperature (300 K) abd very high pressure, then calculate diameter of the molecules. (Given : $N_{A} = 6.0 \times 10^{23}, R = 0.0821 a t m . L m o l^{- 1} K^{- 1}$ )
Answer Type	Text solution:1
Upvotes	150