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If the absolute temperature of an ideal gas having volume V cm

Question

If the absolute temperature of an ideal gas having volume V $c m^{3}$ is doubled and the pressure is reduced to half, the final volume of gas will be?

0.25

0.50

2 V^{2}

4 V

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If the absolute temperature of an ideal gas having volume V

c m^{3}

is doubled and the pressure is reduced to half, the final volume of gas will be?

12 mins ago

Discuss this question LIVE

12 mins ago

Text solutionVerified

Let

T_{1} = T

∴ T_{2} = 2 T

Let

P_{1} = P

∴ P_{2} = P /2

Given that,

V_{1} = V c m^{3}

P_{1} V_{1} = n R T_{1}

P_{2} V_{2} = n R T_{2}

∴ \frac{P _{1}}{P _{2}} \times \frac{V _{1}}{V _{2}} = \frac{T _{1}}{T _{2}}

∴ (2) (\frac{V}{V _{2}}) = \frac{1}{2}

∴ V_{2} = 4 V c m^{3}

Hence, option

D

is correct.

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Question Text	If the absolute temperature of an ideal gas having volume V $c m^{3}$ is doubled and the pressure is reduced to half, the final volume of gas will be?
Answer Type	Text solution:1
Upvotes	150