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% hydrolysis of 0.1M {C}{H}_{{{3}}}{C}{O}{O}{N}{H}_{{{4}}}, wh

Question

$%$ hydrolysis of 0.1M $C H_{3} C O O N H_{4},$ when $K_{a} (C H_{3} C O O H) = K_{b} (N H_{4} O H) = 1.8 \times 10^{- 5}$ is:

0.55

7.63

0.55 \times 10^{- 2}

7.63 \times 10^{- 3}

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hydrolysis of 0.1M

C H_{3} C O O N H_{4},

when

K_{a} (C H_{3} C O O H) = K_{b} (N H_{4} O H) = 1.8 \times 10^{- 5}

is:

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Question Text	$%$ hydrolysis of 0.1M $C H_{3} C O O N H_{4},$ when $K_{a} (C H_{3} C O O H) = K_{b} (N H_{4} O H) = 1.8 \times 10^{- 5}$ is:
Answer Type	Text solution:1
Upvotes	150