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Rate of chemical reaction

For the reaction, A Products, -{d[A]}{d t}=k and at different

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Hard

Solving time: 4 mins

For the reaction, $A ⟶$ Products, $- \frac{d [ A ]}{d t} = k$ and at different time interval, $[A]$ values are $Time [A] 0 20 mol 5 min 18 mol 10 min 16 mol 15 min 14 mol$ At $20 min$ , rate will be

Name: Video solution 1: For the reaction, A⟶ Products, −dtd[A]=k and at different time interval, [A] values are Time [A]020 mol5 min18 mol10 min16 mol15 min14 mol At 20 min, rate will be
Uploaded: 2022-09-17T05:44:08.000Z
Duration: 7 min
Description: Video solution 1: For the reaction, A⟶ Products, −dtd[A]=k and at different time interval, [A] values are Time [A]020 mol5 min18 mol10 min16 mol15 min14 mol At 20 min, rate will be

12 mol / min

10 mol / min

8 mol / min

0.4 mol / min

Views: 5,897 students

Updated on: Sep 17, 2022

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New Pattern JEE Problems Chemistry for JEE Main and Advance( Master Problem Package) (Arihant)

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Theodore Discussed

For the reaction,

A ⟶

Products,

- \frac{d [ A ]}{d t} = k

and at different time interval,

[A]

values are

Time [A] 0 20 mol 5 min 18 mol 10 min 16 mol 15 min 14 mol

20 min

, rate will be

15 mins ago

Discuss this question LIVE

15 mins ago

Text solutionVerified

(d)

\frac{d x}{d t} = k

Rate is constant but concentration of the reactant decreases linearly. At

20 min [A] = 12 mol

Thus,

Δ x = 20 - 12 = 8 mol

Δ t = 20.0 = 20 min

\frac{Δ x}{Δ t} = \frac{8}{20} = 0.4 mol / min

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Question Text	For the reaction, $A ⟶$ Products, $- \frac{d [ A ]}{d t} = k$ and at different time interval, $[A]$ values are $Time [A] 0 20 mol 5 min 18 mol 10 min 16 mol 15 min 14 mol$ At $20 min$ , rate will be
Updated On	Sep 17, 2022
Topic	Chemical Kinetics
Subject	Chemistry
Class	Class 12
Answer Type	Text solution:1 Video solution: 2
Upvotes	273
Avg. Video Duration	5 min

For the reaction, $A ⟶$ Products, $- \frac{d [ A ]}{d t} = k$ and at different time interval, $[A]$ values are $Time [A] 0 20 mol 5 min 18 mol 10 min 16 mol 15 min 14 mol$ At $20 min$ , rate will be

Text solutionVerified

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Text solutionVerified

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For the reaction, $A ⟶$ Products, $- \frac{d [ A ]}{d t} = k$ and at different time interval, $[A]$ values are $Time [A] 0 20 mol 5 min 18 mol 10 min 16 mol 15 min 14 mol$ At $20 min$ , rate will be