Fischer esterification is represented as follows R−C∣∣O−O16−H+R′−O18H⇔R−C∣∣O−OA−R′+H2O here (R=CH3,R′=C2H5) in the above reaction A/2 is equal to

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Fischer esterification is represented as follows $R - C ∣ ∣ O - O 16 - H + R^{'} - O 18 H \Leftrightarrow R - C ∣ ∣ O - O A - R^{'} + H_{2} O$ here $(R = C H_{3}, R^{'} = C_{2} H_{5})$ in the above reaction A/2 is equal to

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Fischer esterification is represented as follows

R - C ∣ ∣ O - O 16 - H + R^{'} - O 18 H \Leftrightarrow R - C ∣ ∣ O - O A - R^{'} + H_{2} O

here

(R = C H_{3}, R^{'} = C_{2} H_{5})

in the above reaction A/2 is equal to

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Question Text	Fischer esterification is represented as follows $R - C ∣ ∣ O - O 16 - H + R^{'} - O 18 H \Leftrightarrow R - C ∣ ∣ O - O A - R^{'} + H_{2} O$ here $(R = C H_{3}, R^{'} = C_{2} H_{5})$ in the above reaction A/2 is equal to
Answer Type	Video solution: 1
Upvotes	151