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Thermodynamics and Thermochemistry

Enthalpy of reaction

Consider the reaction, 4 {NO}_{2}(g)+{O}_{2}(g) 2 {~N}_{2} {O

Question

Medium

Solving time: 3 mins

Consider the reaction, $4 NO_{2} (g) + O_{2} (g) \to 2 N_{2} O_{5} (g), Δ_{r} H = - 111 kJ$ . If $N_{2} O_{5} (s)$ is formed instead of $N_{2} O_{5} (g)$ in the above reaction, the $Δ_{r} H$ value will be (Given, $Δ H$ of sublimation for $N_{2} O_{5}$ is $54 kJ mol^{- 1}$ )

- 165 kJ

+ 54 kJ

+ 219 kJ

- 219 kJ

Views: 6,003 students

Updated on: Mar 14, 2023

Book:

Arihant Chemistry JEE Main Chapterwise Solutions (2019-2002) (Arihant)

Exam:

JEE Mains 2018

Found 6 tutors discussing this question

Ava Discussed

Consider the reaction,

4 NO_{2} (g) + O_{2} (g) \to 2 N_{2} O_{5} (g), Δ_{r} H = - 111 kJ

. If

N_{2} O_{5} (s)

is formed instead of

N_{2} O_{5} (g)

in the above reaction, the

Δ_{r} H

value will be (Given,

Δ H

of sublimation for

N_{2} O_{5}

54 kJ mol^{- 1}

)

12 mins ago

Discuss this question LIVE

12 mins ago

Text solutionVerified

From Hess law,

Δ H_{f} + Δ H_{sub} = Δ H_{reaction}

Δ H_{f} = Δ H_{reaction} - Δ H_{sub}

= - 111 kJ - (54 kJ)

= - 111 - 54 kJ = - 165 kJ

Thus, the enthalpy of formation,

Δ H_{f}

for

N_{2} O_{5}

(s) is

- 165 kJ

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Question Text	Consider the reaction, $4 NO_{2} (g) + O_{2} (g) \to 2 N_{2} O_{5} (g), Δ_{r} H = - 111 kJ$ . If $N_{2} O_{5} (s)$ is formed instead of $N_{2} O_{5} (g)$ in the above reaction, the $Δ_{r} H$ value will be (Given, $Δ H$ of sublimation for $N_{2} O_{5}$ is $54 kJ mol^{- 1}$ )
Updated On	Mar 14, 2023
Topic	Thermodynamics and Thermochemistry
Subject	Chemistry
Class	Class 11
Answer Type	Text solution:1 Video solution: 3
Upvotes	453
Avg. Video Duration	3 min

Consider the reaction, $4 NO_{2} (g) + O_{2} (g) \to 2 N_{2} O_{5} (g), Δ_{r} H = - 111 kJ$ . If $N_{2} O_{5} (s)$ is formed instead of $N_{2} O_{5} (g)$ in the above reaction, the $Δ_{r} H$ value will be (Given, $Δ H$ of sublimation for $N_{2} O_{5}$ is $54 kJ mol^{- 1}$ )

Text solutionVerified

Filo tutor solutions (3)

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Consider the reaction, 4NO2​(g)+O2​(g)→2 N2​O5​(g),Δr​H=−111 kJ. If N2​O5​(s) is formed instead of N2​O5​(g) in the above reaction, the Δr​H value will be (Given, ΔH of sublimation for N2​O5​ is 54 kJ mol−1 )

Text solutionVerified

Filo tutor solutions (3)

Questions from JEE Mains 2018 - PYQs

Practice questions from Arihant Chemistry JEE Main Chapterwise Solutions (2019-2002) (Arihant)

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Consider the reaction, $4 NO_{2} (g) + O_{2} (g) \to 2 N_{2} O_{5} (g), Δ_{r} H = - 111 kJ$ . If $N_{2} O_{5} (s)$ is formed instead of $N_{2} O_{5} (g)$ in the above reaction, the $Δ_{r} H$ value will be (Given, $Δ H$ of sublimation for $N_{2} O_{5}$ is $54 kJ mol^{- 1}$ )