Calculate the total pressure in a mixture of 8 g of dioxygen and 4 g of dihydrogen confined in a vessel of 1 dm3 at 27 ∘C. (R = 0.083 bar dm3 K−1 mol−1)
Solution: The partial pressure of oxygen is P=VnRT=32×18×0.083×300=0.225bar. The partial pressure of hydrogen gas is P′=V′n′RT=12×0.083×300=49.8bar. Total pressure of the mixture=6.225+49.8=56.025bar.