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Calculate relative rates of effusion of {S}{O}_{{{2}}} to {C}{

Question

Calculate relative rates of effusion of $S O_{2}$ to $C H_{4}$ in the mixture obtained by effusing out a mixture with initial molar ratio $\frac{n _{S O_{2}}}{n _{C H_{4}}} = \frac{8}{1}$ for three effusing steps.

2 : 1

1 : 4

1 : 2

none of these

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Calculate relative rates of effusion of

S O_{2}

C H_{4}

in the mixture obtained by effusing out a mixture with initial molar ratio

\frac{n _{S O_{2}}}{n _{C H_{4}}} = \frac{8}{1}

for three effusing steps.

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Text solutionVerified

Answer: cSolution: (c)

\frac{n _{C H_{4}}}{8 / 1} \frac{n _{S O_{2}}^{3}}{3} = (\frac{16}{64})^{3 / 2} \times = \frac{1}{1},

\frac{r _{S O_{2}}}{r _{C H_{4}}} = \frac{1}{1} . \frac{16}{64} = \frac{1}{2}

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Question Text	Calculate relative rates of effusion of $S O_{2}$ to $C H_{4}$ in the mixture obtained by effusing out a mixture with initial molar ratio $\frac{n _{S O_{2}}}{n _{C H_{4}}} = \frac{8}{1}$ for three effusing steps.
Answer Type	Text solution:1
Upvotes	150