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Some Basic Concepts of Chemistry

Stoichiometry and Stoichiometric calculations

At 300 {~K} and 1 atmospheric pressure, 10 {~mL} of a hydrocar

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At $300 K$ and 1 atmospheric pressure, $10 mL$ of a hydrocarbon required $55 mL$ of $O_{2}$ for complete combustion and $40 mL$ of $CO_{2}$ is formed. The formula of the hydrocarbon is (a) $C_{4} H_{7} Cl$ (b) $C_{4} H_{6}$ (d) $C_{4} H_{8}$ (c) $C_{4} H_{10}$

Views: 6,490 students

Updated on: Sep 14, 2023

Book:

Arihant Chemistry JEE Main Chapterwise Solutions (2019-2002) (Arihant)

Exam:

JEE Mains 2019

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300 K

and 1 atmospheric pressure,

10 mL

of a hydrocarbon required

55 mL

O_{2}

for complete combustion and

40 mL

CO_{2}

is formed. The formula of the hydrocarbon is (a)

C_{4} H_{7} Cl

(b)

C_{4} H_{6}

(d)

C_{4} H_{8}

(c)

C_{4} H_{10}

6 mins ago

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6 mins ago

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Question Text	At $300 K$ and 1 atmospheric pressure, $10 mL$ of a hydrocarbon required $55 mL$ of $O_{2}$ for complete combustion and $40 mL$ of $CO_{2}$ is formed. The formula of the hydrocarbon is (a) $C_{4} H_{7} Cl$ (b) $C_{4} H_{6}$ (d) $C_{4} H_{8}$ (c) $C_{4} H_{10}$
Updated On	Sep 14, 2023
Topic	Some Basic Concepts of Chemistry
Subject	Chemistry
Class	Class 11
Answer Type	Text solution:1 Video solution: 23
Upvotes	2230
Avg. Video Duration	9 min

At $300 K$ and 1 atmospheric pressure, $10 mL$ of a hydrocarbon required $55 mL$ of $O_{2}$ for complete combustion and $40 mL$ of $CO_{2}$ is formed. The formula of the hydrocarbon is (a) $C_{4} H_{7} Cl$ (b) $C_{4} H_{6}$ (d) $C_{4} H_{8}$ (c) $C_{4} H_{10}$

Text solutionVerified

Filo tutor solutions (23)

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At 300 K and 1 atmospheric pressure, 10 mL of a hydrocarbon required 55 mL of O2​ for complete combustion and 40 mL of CO2​ is formed. The formula of the hydrocarbon is (a) C4​H7​Cl (b) C4​H6​ (d) C4​H8​ (c) C4​H10​

Text solutionVerified

Filo tutor solutions (23)

Questions from JEE Mains 2019 - PYQs

Practice questions from Arihant Chemistry JEE Main Chapterwise Solutions (2019-2002) (Arihant)

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At $300 K$ and 1 atmospheric pressure, $10 mL$ of a hydrocarbon required $55 mL$ of $O_{2}$ for complete combustion and $40 mL$ of $CO_{2}$ is formed. The formula of the hydrocarbon is (a) $C_{4} H_{7} Cl$ (b) $C_{4} H_{6}$ (d) $C_{4} H_{8}$ (c) $C_{4} H_{10}$