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A student forgot to add the reaction mixture to the round bott

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A student forgot to add the reaction mixture to the round bottomed flask at $27^{o} C$ but instead he/she placed the flask on the flame. After a lapse of time, he realized his mistake, and using a pyrometer he found the temperature of the flask was $477^{o} C$ . What fraction of air would have been expelled out?

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A student forgot to add the reaction mixture to the round bottomed flask at

27^{o} C

but instead he/she placed the flask on the flame. After a lapse of time, he realized his mistake, and using a pyrometer he found the temperature of the flask was

477^{o} C

. What fraction of air would have been expelled out?

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Text solutionVerified

The initial temperature

T = 2 7^{o} C = 27 + 273 K = 300 K

The final temperature

T^{'} = 47 7^{o} C = 477 + 273 K = 750 K

The inital volume is V L and the final volume is V' L.

\frac{V}{V ^{'}} = \frac{T}{T ^{'}}

\frac{V}{V ^{'}} = \frac{300}{750}

\frac{V}{V ^{'}} = \frac{2}{5 ^{'}}

The fraction of air expelled is

1 - \frac{V}{V ^{'}} = 1 - \frac{2}{5} = \frac{3}{5}

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Question Text	A student forgot to add the reaction mixture to the round bottomed flask at $27^{o} C$ but instead he/she placed the flask on the flame. After a lapse of time, he realized his mistake, and using a pyrometer he found the temperature of the flask was $477^{o} C$ . What fraction of air would have been expelled out?
Answer Type	Text solution:1
Upvotes	150

Text solutionVerified

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