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Chemistry Part-I

Coordination Compounds

A solution of [Ni(H_{2}O)_{6}]^{2+} is green but a solution of

Chemistry Part-I

Class 12

NCERT

Chapter 1: The Solid State

31 questions

Chapter 2: Solutions

54 questions

Chapter 3: Electrochemistry

28 questions

Chapter 4: Chemical Kinetics

40 questions

Chapter 5: Surface Chemistry

27 questions

Chapter 6: General Principles and Processes of Isolation of Elements

30 questions

Chapter 7: The p-Block Elements

62 questions

Chapter 8: The d-and f-Block Elements

48 questions

Chapter 9: Coordination Compounds

38 questions

F e S O_{4}

solution mixed with

(N H_{4})_{2} S O_{4}

solution in

1 : 1

molar ratio gives the test of

F e^{2 +}

ion but

C u S O_{4}

solution mixed with aqueous ammonia in

1 : 4

molar ratio does not give the test of

C u^{2 +}

ion. Explain why?

A solution of

[N i (H_{2} O)_{6}]^{2 +}

is green but a solution of

[N i (CN)_{4}]^{2 -}

is colourless, Explain.

Amongst the following, the most stable complex is:
(i)

[F e (H_{2} O)_{6}]^{3 +}

(ii)

[F e (N H_{3})_{6}]^{3 +}

(iii)

[F e (C_{2} O_{4})_{3}]^{3 -}

(iv)

[F e C l_{6}]^{3 -}

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Question

Easy

Solving time: 5 mins

A solution of $[N i (H_{2} O)_{6}]^{2 +}$ is green but a solution of $[N i (CN)_{4}]^{2 -}$ is colourless, Explain.

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Chemistry Part-I (NCERT)

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A solution of

[N i (H_{2} O)_{6}]^{2 +}

is green but a solution of

[N i (CN)_{4}]^{2 -}

is colourless, Explain.

11 mins ago

Discuss this question LIVE

11 mins ago

Text solutionVerified

In both complexes,

N i

is in +2 oxidation state with a valence shell electronic configuration of

3 d^{8}

.In the presence of weak field water ligands, two unpaired electrons do not pair up.

[N i (H_{2} O)_{6}]^{2 +}

.Due to d-d transition, red light is absorbed and complimentary light emitted is green.In presence of strong field cyanide ligand, the unpaired electrons in 3d orbital pair up.

[N i (CN)_{4}]^{2 -}

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Practice more questions from Chemistry Part-I (NCERT)

F e S O_{4}

solution mixed with

(N H_{4})_{2} S O_{4}

solution in

1 : 1

molar ratio gives the test of

F e^{2 +}

ion but

C u S O_{4}

solution mixed with aqueous ammonia in

1 : 4

molar ratio does not give the test of

C u^{2 +}

ion. Explain why?

A solution of

[N i (H_{2} O)_{6}]^{2 +}

is green but a solution of

[N i (CN)_{4}]^{2 -}

is colourless, Explain.

Amongst the following, the most stable complex is:
(i)

[F e (H_{2} O)_{6}]^{3 +}

(ii)

[F e (N H_{3})_{6}]^{3 +}

(iii)

[F e (C_{2} O_{4})_{3}]^{3 -}

(iv)

[F e C l_{6}]^{3 -}

View all

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Question Text	A solution of $[N i (H_{2} O)_{6}]^{2 +}$ is green but a solution of $[N i (CN)_{4}]^{2 -}$ is colourless, Explain.
Topic	Coordination Compounds
Subject	Chemistry
Class	Class 12
Answer Type	Text solution:1
Upvotes	3

A solution of $[N i (H_{2} O)_{6}]^{2 +}$ is green but a solution of $[N i (CN)_{4}]^{2 -}$ is colourless, Explain.

Text solutionVerified

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A solution of $[N i (H_{2} O)_{6}]^{2 +}$ is green but a solution of $[N i (CN)_{4}]^{2 -}$ is colourless, Explain.