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A sodium salt of unknown anion when treated with MgCl_2 gives

Question

A sodium salt of unknown anion when treated with $M g C l_{2}$ gives white precipitate only on boiling the anion is

S O_{4}^{2 -}

H C O_{3}^{-}

C O_{3}^{2 -}

N O_{3}^{-}

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A sodium salt of unknown anion when treated with

M g C l_{2}

gives white precipitate only on boiling the anion is

9 mins ago

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Text solutionVerified

Bicarbonates on heating from insoluble carbonates

M g C l_{2} + 2 N a H C O_{3} \to N a Cl + M g (H C O_{3})_{2}

M g (H C O_{3})_{2} Δ M g C O_{3} ↓ + C O_{2} + H_{2} O

Hence, Option "B" is the correct answer.

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Question Text	A sodium salt of unknown anion when treated with $M g C l_{2}$ gives white precipitate only on boiling the anion is
Answer Type	Text solution:1
Upvotes	150