A rigid vessel of volume 0.50m3 containing H2 at 20.5∘C and a pressure of 611×103 Pa is connected to a second rigid vessel of volume 0.75m3 containing Ar at 31.2∘C at a pressure of 433×103 Pa. A value separating the two vessels is opened and both are cooled to a temperature of 14.5∘C. What is the final pressure in the vessels?

Answer: dSolution: (d) nT=n2+n2 R×287.5P×1.25=293.5R611×103×0.5+204.5R433×103×0.75 P=4.84×105Pa

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A rigid vessel of volume {0.50}{m}^{{{3}}} containing {H}_{{{2

Question

A rigid vessel of volume $0.50 m^{3}$ containing $H_{2}$ at $20.5^{\circ} C$ and a pressure of $611 \times 10^{3}$ Pa is connected to a second rigid vessel of volume 0.75 $m^{3}$ containing Ar at $31.2^{\circ} C$ at a pressure of $433 \times 10^{3}$ Pa. A value separating the two vessels is opened and both are cooled to a temperature of $14.5^{\circ} C$ . What is the final pressure in the vessels?

2 \times 10^{5}

3.22 \times 10^{5} Pa

4840 pa

4.84 \times 10^{5} Pa

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A rigid vessel of volume

0.50 m^{3}

containing

H_{2}

20.5^{\circ} C

and a pressure of

611 \times 10^{3}

Pa is connected to a second rigid vessel of volume 0.75

m^{3}

containing Ar at

31.2^{\circ} C

at a pressure of

433 \times 10^{3}

Pa. A value separating the two vessels is opened and both are cooled to a temperature of

14.5^{\circ} C

. What is the final pressure in the vessels?

6 mins ago

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Answer: dSolution: (d)

n_{T} = n_{2} + n_{2}

\frac{P \times 1.25}{R \times 287.5} = \frac{611 \times 10 ^{3} \times 0.5}{293.5 R} + \frac{433 \times 10 ^{3} \times 0.75}{204.5 R}

P = 4.84 \times 10^{5} P a

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Question Text	A rigid vessel of volume $0.50 m^{3}$ containing $H_{2}$ at $20.5^{\circ} C$ and a pressure of $611 \times 10^{3}$ Pa is connected to a second rigid vessel of volume 0.75 $m^{3}$ containing Ar at $31.2^{\circ} C$ at a pressure of $433 \times 10^{3}$ Pa. A value separating the two vessels is opened and both are cooled to a temperature of $14.5^{\circ} C$ . What is the final pressure in the vessels?
Answer Type	Text solution:1
Upvotes	150