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A 3:2 molar mixture of He and SO_2 is contained in a vessel at

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A 3:2 molar mixture of He and $S O_{2}$ is contained in a vessel at 10 bar pressure. Due to a hole in the vessel the gas mixture leaks out. What is the composition of the mixture effusing out initially?

2:3

1:4

3: 7

6:1

Views: 6,515 students

Updated on: Feb 15, 2023

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Isabella Discussed

A 3:2 molar mixture of He and

S O_{2}

is contained in a vessel at 10 bar pressure. Due to a hole in the vessel the gas mixture leaks out. What is the composition of the mixture effusing out initially?

14 mins ago

Discuss this question LIVE

14 mins ago

Text solutionVerified

P_{He} = \frac{3}{5} \times 10 or 6 ba r

P_{He} = \frac{3}{5} \times 10 or 6 ba r

Rate of effusion

= k \frac{P}{M}

Where k is constant , P is the partial pressure of the gas , M is the molar mass , and its value for He = 4 g / mol and for

S O_{2}

= 64 g/mol.
Pressure = 10 bar
Molar ratio = 3:2

P_{He} = \frac{3}{5} \times 10 or 6 ba r

P_{S O_{2}} = \frac{2}{5} \times 10 or 4 ba r

\frac{R a t e o f e ff u s i o n o f He}{R a t e o f e ff u s i o n o f S O _{2}}

= \frac{6/ 4}{4/ 64} = \frac{48}{8} = 6 : 1

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Question Text	A 3:2 molar mixture of He and $S O_{2}$ is contained in a vessel at 10 bar pressure. Due to a hole in the vessel the gas mixture leaks out. What is the composition of the mixture effusing out initially?
Updated On	Feb 15, 2023
Topic	States of Matter
Subject	Chemistry
Class	Class 11
Answer Type	Text solution:1 Video solution: 7
Upvotes	657
Avg. Video Duration	8 min

A 3:2 molar mixture of He and $S O_{2}$ is contained in a vessel at 10 bar pressure. Due to a hole in the vessel the gas mixture leaks out. What is the composition of the mixture effusing out initially?

Text solutionVerified

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A 3:2 molar mixture of He and $S O_{2}$ is contained in a vessel at 10 bar pressure. Due to a hole in the vessel the gas mixture leaks out. What is the composition of the mixture effusing out initially?