Class 12 Chemistry Gases & Solutions States Of Matter

500 mL of nitrogen at $27_{∘}C$ is cooled to $−5_{∘}C$ at the same pressure. The new volume becomes

(a)

326.32 mL

(b)

446.66 mL

(c)

546.32 mL

(d)

771.56 mL

Correct answer: (b)

Solution: Initial volume, $V_{1}=500mL$

Initial temperature,

$T_{1}=27_{∘}C=27+273=300K$

Final temperature,

$T_{2}=−5+273=268K$

$V_{2}=?$

$T_{1}V_{1} =T_{2}V_{2} $

$V_{2}=T_{1}V_{1}T_{2} =300500×268 $

$=446.66mL$

Initial temperature,

$T_{1}=27_{∘}C=27+273=300K$

Final temperature,

$T_{2}=−5+273=268K$

$V_{2}=?$

$T_{1}V_{1} =T_{2}V_{2} $

$V_{2}=T_{1}V_{1}T_{2} =300500×268 $

$=446.66mL$

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