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50 {~mL} of each gas A and of gas B takes 150 and 200 seconds

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Medium

Solving time: 3 mins

$50 m L$ of each gas $A$ and of gas $B$ takes $150$ and $200$ seconds respectively for effusing through a pin hole under the similar conditions. If molecular mass of gas $B$ is $36 u$ , the molecular mass of gas $A$ will be:

20.2 u

64 u

96 u

128 u

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Updated on: Sep 9, 2023

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Emily Discussed

50 m L

of each gas

A

and of gas

B

takes

150

and

200

seconds respectively for effusing through a pin hole under the similar conditions. If molecular mass of gas

B

36 u

, the molecular mass of gas

A

will be:

6 mins ago

Discuss this question LIVE

6 mins ago

Text solutionVerified

Given:

V_{A} = V_{B} = 50 m L

T_{A} = 150 s

T_{B} = 200 s

M_{B} = 36 u

M_{A} = ?

From Graham's law of effusion

\frac{r _{B}}{r _{A}} = \frac{M _{A}}{M _{B}} = \frac{V _{B} \times T _{A}}{T _{B} \times V _{A}}

\Rightarrow \frac{M _{A}}{36} = \frac{V _{A} \times 150}{200 \times V _{A}}

\frac{M _{A}}{36} = \frac{15}{20} = \frac{3}{4}

\frac{M _{A}}{36} = \frac{9}{16}

M_{A} = \frac{9 \times 36}{16} = \frac{9 \times 9}{4} = \frac{81}{4} = 20.2 u

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Question Text	$50 m L$ of each gas $A$ and of gas $B$ takes $150$ and $200$ seconds respectively for effusing through a pin hole under the similar conditions. If molecular mass of gas $B$ is $36 u$ , the molecular mass of gas $A$ will be:
Updated On	Sep 9, 2023
Topic	States of Matter
Subject	Chemistry
Class	Class 11
Answer Type	Text solution:1 Video solution: 11
Upvotes	1251
Avg. Video Duration	8 min

$50 m L$ of each gas $A$ and of gas $B$ takes $150$ and $200$ seconds respectively for effusing through a pin hole under the similar conditions. If molecular mass of gas $B$ is $36 u$ , the molecular mass of gas $A$ will be:

Text solutionVerified

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50 mL of each gas A and of gas B takes 150 and 200 seconds respectively for effusing through a pin hole under the similar conditions. If molecular mass of gas B is 36u , the molecular mass of gas A will be:

Text solutionVerified

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$50 m L$ of each gas $A$ and of gas $B$ takes $150$ and $200$ seconds respectively for effusing through a pin hole under the similar conditions. If molecular mass of gas $B$ is $36 u$ , the molecular mass of gas $A$ will be: