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Some Basic Concepts of Chemistry

Molarity

50 {~mL} of 0.5 {M} oxalic acid is needed to neutralise 25 {~m

Question

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Solving time: 3 mins

$50 mL$ of $0.5 M$ oxalic acid is needed to neutralise $25 mL$ of sodium hydroxide solution. The amount of $NaOH$ in $50 mL$ of the given sodium hydroxide solution is

40 g

80 g

20 g

none of these

Views: 6,110 students

Updated on: Feb 6, 2024

Book:

Arihant Chemistry JEE Main Chapterwise Solutions (2019-2002) (Arihant)

Exam:

JEE Mains 2019

Found 5 tutors discussing this question

Asher Discussed

50 mL

0.5 M

oxalic acid is needed to neutralise

25 mL

of sodium hydroxide solution. The amount of

NaOH

50 mL

of the given sodium hydroxide solution is

9 mins ago

Discuss this question LIVE

9 mins ago

Text solutionVerified

Exp \cdot (^{*})

The reaction takes place as follows,

H_{2} C_{2} O_{4} + 2 NaOH ⟶ Na_{2} C_{2} O_{4} + 2 H_{2} O

Now,

50 mL

0.5 M H_{2} C_{2} O_{4}

is needed to neutralize

25 mL

NaOH

∴ Meq of H_{2} C_{2} O_{4} = Meq of NaOH

50 \times 0.5 \times 2 = 25 \times M_{NaOH} \times 1

M_{NaOH} = 2 M

Now, molarity = \frac{Number of moles}{Volume of solution (in L )}

= \frac{Weight / molecular mass}{Volume of solution (in L )}

2 = \frac{W _{NaOH}}{40} \times \frac{1000}{50}

W_{NaOH} = \frac{2 \times 40 \times 50}{1000} = 4 g

Thus, (

D)

none option is correct.

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Question Text	$50 mL$ of $0.5 M$ oxalic acid is needed to neutralise $25 mL$ of sodium hydroxide solution. The amount of $NaOH$ in $50 mL$ of the given sodium hydroxide solution is
Updated On	Feb 6, 2024
Topic	Some Basic Concepts of Chemistry
Subject	Chemistry
Class	Class 11
Answer Type	Text solution:1 Video solution: 10
Upvotes	1234
Avg. Video Duration	8 min

$50 mL$ of $0.5 M$ oxalic acid is needed to neutralise $25 mL$ of sodium hydroxide solution. The amount of $NaOH$ in $50 mL$ of the given sodium hydroxide solution is

Text solutionVerified

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$50 mL$ of $0.5 M$ oxalic acid is needed to neutralise $25 mL$ of sodium hydroxide solution. The amount of $NaOH$ in $50 mL$ of the given sodium hydroxide solution is