4 gm of sulphur dioxide gas diffuses from a container in 8 min. Mass of helium gas diffusing from the same container over the same time interval is :

0.5 g

1 g

2 g

None of these

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4 gm of sulphur dioxide gas diffuses from a container in 8 min. Mass of helium gas diffusing from the same container over the same time interval is :

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Answer: bSolution: (b)

\frac{n _{1} . t _{2}}{n _{2} . t _{1}} = \frac{M _{2}}{M _{1}}, \frac{w _{1}}{M _{1}} \times \frac{M _{2}}{w _{2}} = \frac{M _{2}}{M _{1}}

\frac{w _{1}}{w _{2}} = \frac{M _{1}}{M _{2}}, \frac{w _{1}}{4} = \frac{4}{64}

\Rightarrow w_{1} = 1 gm

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Question Text	4 gm of sulphur dioxide gas diffuses from a container in 8 min. Mass of helium gas diffusing from the same container over the same time interval is :
Answer Type	Text solution:1
Upvotes	150