The radio nuclide ^{11}C decays according to^{11}_{6}C\, \rightarr | Filo
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Class 12


Cell: Structure and Functions


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The radio nuclide decays according to

The maximum energy of the emitted positron is
Given the mass values:
Calculate and compare it with the maximum energy of the positron emitted.


Where, the masses used are those of nuclei and not of atoms. If we use atomic masses, we have to add in case of and in case of . Hence,
(Note has been doubled)
Using given masses, Q = 0.961 MeV.
Q =
The daughter nucleus is too heavy compared to and , so it carries negligible energy (  0). If the kinetic energy () carried by the neutrino is minimum (i.e., zero), the positron carries maximum energy, and this is practically all energy Q, hence, maximum  Q.
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