The radio nuclide ^{11}C decays according to^{11}_{6}C\, \rightarr | Filo
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Class 12

Biology

Cell: Structure and Functions

Nuclei

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The radio nuclide decays according to

The maximum energy of the emitted positron is
Given the mass values:
and 
Calculate and compare it with the maximum energy of the positron emitted.

Solution:

Where, the masses used are those of nuclei and not of atoms. If we use atomic masses, we have to add in case of and in case of . Hence,
(Note has been doubled)
Using given masses, Q = 0.961 MeV.
Q =
The daughter nucleus is too heavy compared to and , so it carries negligible energy (  0). If the kinetic energy () carried by the neutrino is minimum (i.e., zero), the positron carries maximum energy, and this is practically all energy Q, hence, maximum  Q.
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