The neutron separation energy is defined as the energy required to remove a neutron from the nucleus. Obtain the neutron separation energy of the nuclei 1327Al from the following data: m(1326Al)=25.986895u m(1327Al)=26.981541u
Solution: The reaction for the neutron separation from the aluminum atom is
We know that, the separation energy can be calculated as:
On the other hand 1u=931.5MeV/c2
So, the energy of neutron separation will be:
Therefore to remove a neutron from the nucleus 13.059MeV of energy is required.