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Physics Part-II

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The neutron separation energy is defined as the energy require

Physics Part-II

Class 12

NCERT

Chapter 1: Ray Optics and Optical Instruments

41 questions

Chapter 2: Wave Optics

30 questions

Chapter 3: Dual Nature of Radiation and Matter

44 questions

Chapter 4: Atoms

23 questions

Chapter 5: Nuclei

38 questions

In a periodic table the average atomic mass of magnesium is given as 24.312 u. The average value is based on their relative natural abundance on earth. The three isotopes and their masses are

_{12}^{24} M g

(23.98504u),

_{12}^{25} M g

(24.98584u) and

_{12}^{26} M g

(25.98259u). The natural abundance of

_{12}^{24} M g

is 78.99% by mass. Calculate the abundances of other two isotopes.

The neutron separation energy is defined as the energy required to remove a neutron from the nucleus. Obtain the neutron separation energy of the nuclei

_{13}^{27} A l

from the following data:

m (_{13}^{26} A l) = 25.986895 u

m (_{13}^{27} A l) = 26.981541 u

A source contains two phosphorous radio nuclides

_{15}^{32} P (T_{1/2} = 14.3 d)

and

_{15}^{33} P (T_{1/2} = 25.3 d)

. Initially, 10% of the decays come from

_{15}^{32} P

. How long one must wait until 90% to do so?

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Chapter 6: Semiconductor Electronics: Materials, Devices and Simple Circuits

25 questions

Question

Medium

Solving time: 4 mins

The neutron separation energy is defined as the energy required to remove a neutron from the nucleus. Obtain the neutron separation energy of the nuclei $_{13}^{27} A l$ from the following data:
$m (_{13}^{26} A l) = 25.986895 u$
$m (_{13}^{27} A l) = 26.981541 u$

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Physics Part-II (NCERT)

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Elijah Discussed

The neutron separation energy is defined as the energy required to remove a neutron from the nucleus. Obtain the neutron separation energy of the nuclei

_{13}^{27} A l

from the following data:

m (_{13}^{26} A l) = 25.986895 u

m (_{13}^{27} A l) = 26.981541 u

15 mins ago

Discuss this question LIVE

15 mins ago

Text solutionVerified

The reaction for the neutron separation from the aluminum atom is

_{13}^{27} A l + E \to_{13}^{26} A l +_{0}^{1} n

We know that, the separation energy can be calculated as:

E = (m (_{13}^{26} C a) + m (_{0}^{1} n) - m (_{13}^{27} C a)) c^{2}

= (25.986895 + 1.008665 - 260981541) c^{2}

= (0.014019) u \times c^{2}

On the other hand

1 u = 931.5 M e V / c^{2}

So, the energy of neutron separation will be:

E = (0.014019) \times 931.5

= 13.059 M e V

Therefore to remove a neutron from the nucleus

13.059 M e V

of energy is required.

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Practice more questions from Physics Part-II (NCERT)

In a periodic table the average atomic mass of magnesium is given as 24.312 u. The average value is based on their relative natural abundance on earth. The three isotopes and their masses are

_{12}^{24} M g

(23.98504u),

_{12}^{25} M g

(24.98584u) and

_{12}^{26} M g

(25.98259u). The natural abundance of

_{12}^{24} M g

is 78.99% by mass. Calculate the abundances of other two isotopes.

The neutron separation energy is defined as the energy required to remove a neutron from the nucleus. Obtain the neutron separation energy of the nuclei

_{13}^{27} A l

from the following data:

m (_{13}^{26} A l) = 25.986895 u

m (_{13}^{27} A l) = 26.981541 u

A source contains two phosphorous radio nuclides

_{15}^{32} P (T_{1/2} = 14.3 d)

and

_{15}^{33} P (T_{1/2} = 25.3 d)

. Initially, 10% of the decays come from

_{15}^{32} P

. How long one must wait until 90% to do so?

View all

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Question Text	The neutron separation energy is defined as the energy required to remove a neutron from the nucleus. Obtain the neutron separation energy of the nuclei $_{13}^{27} A l$ from the following data: $m (_{13}^{26} A l) = 25.986895 u$ $m (_{13}^{27} A l) = 26.981541 u$
Topic	Nuclei
Subject	Physics
Class	Class 12
Answer Type	Text solution:1
Upvotes	79

The neutron separation energy is defined as the energy required to remove a neutron from the nucleus. Obtain the neutron separation energy of the nuclei $_{13}^{27} A l$ from the following data:
$m (_{13}^{26} A l) = 25.986895 u$
$m (_{13}^{27} A l) = 26.981541 u$

Text solutionVerified

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The neutron separation energy is defined as the energy required to remove a neutron from the nucleus. Obtain the neutron separation energy of the nuclei 1327​Al from the following data:m(1326​Al)=25.986895um(1327​Al)=26.981541u

Text solutionVerified

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The neutron separation energy is defined as the energy required to remove a neutron from the nucleus. Obtain the neutron separation energy of the nuclei $_{13}^{27} A l$ from the following data:
$m (_{13}^{26} A l) = 25.986895 u$
$m (_{13}^{27} A l) = 26.981541 u$