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Physics Part-II

Obtain the binding energy (in MeV) of a nitrogen nucleus (

Physics Part-II

Physics Part-II

Class 12

NCERT

Chapter 1: Ray Optics and Optical Instruments

41 questions

Chapter 2: Wave Optics

30 questions

Chapter 3: Dual Nature of Radiation and Matter

44 questions

Chapter 4: Atoms

23 questions

Chapter 5: Nuclei

38 questions

The three stable isotopes of neon:

_{10}^{20} Ne

_{10}^{21} Ne

_{10}^{22} Ne

have respective abundances of 90.51%, 0.27% and 9.22%. The atomic masses of the three isotopes are 19.99 u, 20.99 u and 21.99 u, respectively. Obtain the average atomic mass of neon.

Obtain the binding energy (in MeV) of a nitrogen nucleus

(_{7}^{14} N)

(_{7}^{14} N)

Obtain the binding energy of the nuclei

_{26}^{56} F e

_{83}^{209} B i

in units of MeV from the following data:
(a)

m (_{26}^{56} F e) = 55.934939 u

m (_{83}^{209} B i) = 208.980388 u

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Chapter 6: Semiconductor Electronics: Materials, Devices and Simple Circuits

25 questions

Question

Easy

Solving time: 3 mins

Obtain the binding energy (in MeV) of a nitrogen nucleus $(_{7}^{14} N)$ .

[Given: m $(_{7}^{14} N)$ =14.00307 u.]

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Physics Part-II (NCERT)

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Obtain the binding energy (in MeV) of a nitrogen nucleus

(_{7}^{14} N)

.

[Given: m

(_{7}^{14} N)

=14.00307 u.]

8 mins ago

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8 mins ago

Text solutionVerified

Given:

mass defect.

Δ m = 0.00307 u .

Binding Energy is given by,

E = Δ m \times 931 M e V

= 0.00307 \times 931 = 2.86 M e V

.

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Practice more questions from Physics Part-II (NCERT)

The three stable isotopes of neon:

_{10}^{20} Ne

_{10}^{21} Ne

_{10}^{22} Ne

have respective abundances of 90.51%, 0.27% and 9.22%. The atomic masses of the three isotopes are 19.99 u, 20.99 u and 21.99 u, respectively. Obtain the average atomic mass of neon.

Obtain the binding energy (in MeV) of a nitrogen nucleus

(_{7}^{14} N)

(_{7}^{14} N)

Obtain the binding energy of the nuclei

_{26}^{56} F e

_{83}^{209} B i

in units of MeV from the following data:
(a)

m (_{26}^{56} F e) = 55.934939 u

m (_{83}^{209} B i) = 208.980388 u

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Question Text	Obtain the binding energy (in MeV) of a nitrogen nucleus $(_{7}^{14} N)$ . [Given: m $(_{7}^{14} N)$ =14.00307 u.]
Topic	Nuclei
Subject	Physics
Class	Class 12
Answer Type	Text solution:1
Upvotes	28