Class 12 Biology Cell: Structure and Functions Nuclei

A given coin has a mass of 3.0 g. Calculate the nuclear energy that would be required to separate all the neutrons and protons from each other. For simplicity assume that the coin is entirely made of $_{29}Cu$ atoms (of mass 62.92960 u).

Solution: Number of atoms in a 3g coin=$636.023×10_{23}×3 =2.868×10_{22}$

Each copper atom has 29 protons and and 34 neutrons.

Thus, the mass defect of each atom is $29×1.00783+34×1.00867−62.92960=0.59225u$.

Total mass defect of all atoms = $0.59225u×2.868×10_{22}=1.6985×10_{22}u$.

Thus, the nuclear energy required=$1.6985×10_{22}×931MeV=1.58×10_{25}MeV$.

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