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Temperature dependence

Which of the following lines correctly show the temperature de

Question

Medium

Solving time: 3 mins

Which of the following lines correctly show the temperature dependence of equilibrium constant, $K$ , for an exothermic reaction?

A

and

B

B

and

C

C

and

D

A

and

D

Views: 5,745 students

Updated on: May 3, 2023

Book:

Arihant Chemistry JEE Main Chapterwise Solutions (2019-2002) (Arihant)

Exam:

JEE Mains 2018

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Which of the following lines correctly show the temperature dependence of equilibrium constant,

K

, for an exothermic reaction?

7 mins ago

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Text solutionVerified

From thermodynamics,

ln k = \frac{- Δ H ^{\circ}}{RT} + \frac{Δ S ^{\circ}}{R}

Mathematically, the equation of straight line is

y = c + m x

After comparing Eq. (ii) with (i) we get, slope

= \frac{- Δ H ^{\circ}}{R}

and intercept

= \frac{Δ S ^{\circ}}{R}

Now, we know for exothermic reaction

Δ H

is negative (-)ve. But here,

Slope = \frac{- Δ H ^{\circ}}{R} is positive

So, lines A and B in the graph represent temperature dependence of equilibrium constant K for an exothermic reaction as shown below Solution Image

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Question Text	Which of the following lines correctly show the temperature dependence of equilibrium constant, $K$ , for an exothermic reaction?
Updated On	May 3, 2023
Topic	Equilibrium
Subject	Chemistry
Class	Class 11
Answer Type	Text solution:1 Video solution: 5
Upvotes	748
Avg. Video Duration	8 min

Which of the following lines correctly show the temperature dependence of equilibrium constant, $K$ , for an exothermic reaction?

Text solutionVerified

Filo tutor solutions (5)

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Which of the following lines correctly show the temperature dependence of equilibrium constant, $K$ , for an exothermic reaction?