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Coordination Compounds

Werner's Theory of Coordination Compounds

The volume (in {mL} ) of 0.1 {M} {AgNO}_{3} required for compl

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Solving time: 5 mins

The volume (in $mL$ ) of $0.1 M AgNO_{3}$ required for complete precipitation of chloride ions present in $30 mL$ of $0.01 M$ solution of $[Cr (H_{2} O)_{5} Cl] Cl_{2}$ , as silver chloride is close to

Name: Video solution 1: The volume (in mL ) of 0.1MAgNO3 required for complete precipitation of chloride ions present in 30 mL of 0.01M solution of [Cr(H2O)5Cl]Cl2, as silver chloride is close to
Uploaded: 2023-05-16T02:21:51.000Z
Duration: 10 min
Description: Video solution 1: The volume (in mL ) of 0.1MAgNO3 required for complete precipitation of chloride ions present in 30 mL of 0.01M solution of [Cr(H2O)5Cl]Cl2, as silver chloride is close to

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Updated on: May 16, 2023

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Samuel Discussed

The volume (in

mL

) of

0.1 M AgNO_{3}

required for complete precipitation of chloride ions present in

30 mL

0.01 M

solution of

[Cr (H_{2} O)_{5} Cl] Cl_{2}

, as silver chloride is close to

5 mins ago

Discuss this question LIVE

5 mins ago

Text solutionVerified

mmol of complex

= 30 \times 0.01 = 0.3

Also, 1 mole of complex

[Cr (H_{2} O)_{5} Cl] Cl_{2}

gives only two moles of chloride ion when dissolved in solution

\Rightarrow [Cr (H_{2} O)_{5} Cl] Cl_{2} ⟶ [Cr (H_{2} O)_{5} Cl^{2 +} + 2 Cl^{-} mmol of Cl^{-} ion produced from its 0.3 mmol = 0.6

Hence,

0.6 mmol

Ag^{+}

would be required for precipitation.

\Rightarrow 0.60 mmol of Ag^{+} = 0.1 M \times V (in mL) \Rightarrow V = 6 mL

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Question Text	The volume (in $mL$ ) of $0.1 M AgNO_{3}$ required for complete precipitation of chloride ions present in $30 mL$ of $0.01 M$ solution of $[Cr (H_{2} O)_{5} Cl] Cl_{2}$ , as silver chloride is close to
Updated On	May 16, 2023
Topic	Coordination Compounds
Subject	Chemistry
Class	Class 12
Answer Type	Text solution:1 Video solution: 1
Upvotes	64
Avg. Video Duration	10 min

The volume (in $mL$ ) of $0.1 M AgNO_{3}$ required for complete precipitation of chloride ions present in $30 mL$ of $0.01 M$ solution of $[Cr (H_{2} O)_{5} Cl] Cl_{2}$ , as silver chloride is close to

Text solutionVerified

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The volume (in $mL$ ) of $0.1 M AgNO_{3}$ required for complete precipitation of chloride ions present in $30 mL$ of $0.01 M$ solution of $[Cr (H_{2} O)_{5} Cl] Cl_{2}$ , as silver chloride is close to